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Class 9–10 · Physics

Current electricity

Change it and see

Current electricity

RVI
A closed circuit contains a source, resistor and current path.
Lessons in this chapter
  1. Current and direction
  2. emf and terminal voltage
  3. Ohm's law
  4. Resistivity
  5. Series resistance
  6. Parallel resistance
  7. Circuits and meters
  8. Joule heating and power
  9. Electrical energy use
  10. Fuses, earthing and safety
  11. Cells and junction rules

Lessons

1

Current and direction

RVI
A closed circuit contains a source, resistor and current path.

Current is charge crossing a section per unit time. Conventional current follows positive-charge motion; metal electrons drift oppositely. A source maintains the driving potential difference in a closed circuit. Devices transform energy rather than consuming charge.

Key relationship

I = Q/t; 1 A = 1 C/s

Worked example

12 C in 4 s ⇒ 3 A

2

emf and terminal voltage

RVI
A closed circuit contains a source, resistor and current path.

emf is energy supplied per charge, measured in volts rather than newtons. A discharging cell's internal resistance causes an internal voltage drop, so terminal voltage is below emf.

Key relationship

ε = energy supplied/Q; discharging: V = ε−Ir

Worked example

ε = 1.5 V, r = 0.2 Ω, I = 0.5 A ⇒ V = 1.4 V

3

Ohm's law

RVI
A closed circuit contains a source, resistor and current path.

An ohmic conductor has proportional voltage and current under constant physical conditions, especially temperature. Its V–I slope, with V vertical, is resistance. A heating filament need not remain ohmic over its full operating range.

Key relationship

V = IR; R = V/I; unit Ω

Worked example

V = 6 V, I = 0.3 A ⇒ R = 20 Ω

4

Resistivity

RVI
A closed circuit contains a source, resistor and current path.

Wire resistance increases with length and decreases with cross-sectional area. Resistivity depends on material and temperature. Metals usually gain resistance when heated. Diameter changes affect area quadratically.

Key relationship

R = ρL/A; resistivity unit Ω m

Worked example

Double length and halve area ⇒ resistance becomes 4R

5

Series resistance

RVI
A closed circuit contains a source, resistor and current path.

Series components share one current path. Voltage drops add to the supplied voltage and resistances add. Opening any component breaks that path.

Key relationship

Rs = R₁+R₂+…

Worked example

2 Ω + 4 Ω at 12 V ⇒ I = 12/6 = 2 A; drops 4 V and 8 V

6

Parallel resistance

RVI
A closed circuit contains a source, resistor and current path.

Parallel branches connect across the same two nodes and share voltage. Branch currents add; lower resistance draws more current. The equivalent resistance is below the smallest branch resistance.

Key relationship

1/Rp = 1/R₁+1/R₂+…; I = I₁+I₂

Worked example

6 Ω and 3 Ω across 6 V ⇒ currents 1 A, 2 A; equivalent 2 Ω

7

Circuits and meters

RVI
A closed circuit contains a source, resistor and current path.

Standard symbols clarify circuit structure. Connect an ammeter in series and a voltmeter across the measured component. An ideal ammeter has negligible resistance; an ideal voltmeter has extremely high resistance.

Key relationship

ammeter: series; voltmeter: parallel

Worked example

Measure V and I across/through one resistor ⇒ R = V/I

8

Joule heating and power

RVI
A closed circuit contains a source, resistor and current path.

Electrical power is VI. For an ohmic resistor this becomes I²R or V²/R. Whether greater resistance means greater heating depends on whether current or voltage is held fixed.

Key relationship

H = I²Rt; P = VI = I²R = V²/R

Worked example

I = 2 A, R = 5 Ω, t = 10 s ⇒ H = 200 J, P = 20 W

9

Electrical energy use

RVI
A closed circuit contains a source, resistor and current path.

One billing unit is 1 kWh of energy. Multiply kW by hours. A rating describes operation at specified voltage. This calculation gives energy, not a complete bill with tariffs or fixed charges.

Key relationship

E(kWh) = P(kW)t(h); 1 kWh = 3.6 MJ

Worked example

4 × 60 W × 5 h/day × 30 days = 36 kWh

10

Fuses, earthing and safety

RVI
A closed circuit contains a source, resistor and current path.

A short circuit can draw excessive current and heat wiring. Fuses and breakers interrupt unsafe currents. Protective earthing provides a fault path for exposed conductive parts. Use only the online demonstration; mains work belongs to trained people.

Key relationship

heating ∝ I²R

Worked example

Adding several high-power devices to one outlet raises total current.

11

Cells and junction rules

RVI
A closed circuit contains a source, resistor and current path.

Series cells add emf and internal resistance. Identical parallel cells retain emf and reduce equivalent internal resistance. Junction current balance expresses charge conservation; closed-loop voltage balance expresses energy conservation.

Key relationship

series εtotal = nε; identical parallel rtotal = r/n; ΣIin = ΣIout

Worked example

3 A enters; one outgoing branch has 1 A ⇒ other outgoing branch 2 A

Check your understanding

Try answering first, then open the question to compare your reasoning.

1. 12 V across 4 Ω: current?

I = 12/4 = 3 A

2. Two 6 Ω resistors in parallel?

1/R = 1/6+1/6 ⇒ R = 3 Ω

3. How is a voltmeter connected?

In parallel across the measured component

4. 2 kW device for 3 h: energy?

E = 2 × 3 = 6 kWh

5. Double current at fixed R: heating-power factor?

P = I²R ⇒ 4

Sources and scope

Original GetReady teaching notes. The 13 core chapters follow the existing site sequence. Physics to save life is an explicitly labelled older-edition supplement. Check your current book and board instructions for examination scope. Illustrations are schematic. Unless stated otherwise, use g = 9.8 m/s². A physics teacher should review content and edition coverage before it is relied on.